document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1026867>Question 1026867</A>: <I><SPAN STYLE=\"word-break: break-all;\"> F(x)= 3x-2 over x^2+2x-24 - x-3 over x^2-9      \r<BR>\n" );
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document.write( "So far I have (x+6)(x+4) along with (x+3)(x-3) so if the x-3's cancel each other you're left with 3x-2 over (x+6)(x+4)(x+3)...is that the final?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #642220 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=642220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F(x)= 3x-2 over x^2+2x-24 - x-3 over x^2-9 <BR>\n" );
document.write( "------<BR>\n" );
document.write( "F(x) = (3x-2)/[(x+6)(x-4)] - (x-3)/[(x+3)(x-3)]<BR>\n" );
document.write( "----<BR>\n" );
document.write( "F(x) = (3x-2)/[(x+6)(x-4)] - 1/[(x+3)<BR>\n" );
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document.write( "F(x) = [(x+3)(3x-2)-(x+6)(x-4)]/[(x+3)(x+6)(x-4)]<BR>\n" );
document.write( "------<BR>\n" );
document.write( "F(x) = [3x^2 +7x -6 - x^2 - 2x +24]/[(x+3)(x^2-2x-24)]<BR>\n" );
document.write( "------<BR>\n" );
document.write( "F(x) = [2x^2 +5x + 18]/[(x+3)(x^2-2x-24)]<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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