document.write( "Question 1026950: Jada has a total of 21 coins, only dimes and quarters. She has $3.15.how many of each coins does she have?
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Algebra.Com's Answer #642217 by macston(5194)\"\" \"About 
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\n" ); document.write( "D=number of dimes; Q=number of quarters
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\n" ); document.write( "D+Q=21
\n" ); document.write( "D=21-Q . Use this to substitute for D below.
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\n" ); document.write( "$0.10(D)+$0.25(Q)=$3.15 . Substitute for D from above.
\n" ); document.write( "$0.10(21-Q)+$0.25(Q)=$3.15
\n" ); document.write( "$2.10-$0.10Q+$0.25Q=$3.15
\n" ); document.write( "$0.15Q=$1.05
\n" ); document.write( "Q=7
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\n" ); document.write( "ANSWER 1: She has 7 quarters.
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\n" ); document.write( "D=21-Q=21-7=14
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\n" ); document.write( "ANSWER 2: She has 14 dimes.
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\n" ); document.write( "CHECK:
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\n" ); document.write( "$0.10(D)+$0.25(Q)=$3.15
\n" ); document.write( "$0.10(14)+$0.25(7)=$3.15
\n" ); document.write( "$1.40+$1.75=$3.15
\n" ); document.write( "$3.15=$3.15
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