document.write( "Question 1026951: Suppose that a cyclist began a 352 mi ride across a state at the western edge of the​ state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after 5.5 hr and the car traveled 38.8 mph faster than the​ bicycle, find the average rate of each \n" ); document.write( "
Algebra.Com's Answer #642212 by macston(5194)\"\" \"About 
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\n" ); document.write( "The combined rates of the car and bicycle is 352 mi/5.5 hr=64 mi/hr
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\n" ); document.write( "B=rate of bicycle; C=rate of car=B+38.8 mph
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\n" ); document.write( "B+C=64 mph
\n" ); document.write( "B+(B+38.8mph)=64 mph
\n" ); document.write( "2B+38.8 mph=64 mph
\n" ); document.write( "2B=25.2 mph
\n" ); document.write( "B=12.6 mph
\n" ); document.write( "ANSWER 1: Average rate of bicycle was 12.6 mph.
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\n" ); document.write( "C=B+38.8 mph=12.6 mph+38.8 mph=51.4 mph
\n" ); document.write( "ANSWER 2: Average rate of car was 51.4 mph.
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\n" ); document.write( "CHECK:
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\n" ); document.write( "(Rate of car)(5.5hrs)+(rate of bicycle)(5.5hrs)=352 miles
\n" ); document.write( "(51.4 mph)(5.5 hrs)+(12.6 mph)(5.5 hrs)=352 miles
\n" ); document.write( "282.7 miles + 69.3 miles = 352 miles
\n" ); document.write( "352 miles = 352 miles
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