document.write( "Question 1026930: The temperature of a point (x,y) in the plane is given by the expression x^2 + y^2 - 4x + 2y. What is the temperature of the coldest point in the plane?
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Algebra.Com's Answer #642210 by robertb(5830)\"\" \"About 
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Let \"F+=++x%5E2+%2B+y%5E2+-+4x+%2B+2y\".\r
\n" ); document.write( "\n" ); document.write( "Finding the critical points of F:
\n" ); document.write( "\"F%5Bx%5D+=++2x+-+4+=+0\"==> x = 2, and
\n" ); document.write( "\"F%5By%5D+=++2y+%2B+2+=+0\"==> y = -1.
\n" ); document.write( "==> critical point is (2,-1).
\n" ); document.write( "Also, \"F%5Bxx%5D+=+2+%3E+0\", \"F%5Byy%5D+=+2+%3E+0\", and \"F%5Bxy%5D+=+F%5Byx%5D+=+0\"
\n" ); document.write( "Implement the 2nd derivative test for two variables:
\n" ); document.write( "\"F%5Bxx%5D%2AF%5Byy%5D+-+%28F%5Bxy%5D%29%5E2+=+2%2A2+-+0%5E2+=+4+%3E+0\"\r
\n" ); document.write( "\n" ); document.write( "==> There is local min at (2,-1). Since it is the only critical point in the domain of the function (which is infinite open), it is also an absolute minimum.
\n" ); document.write( "The temperature of the coldest point is thus \"2%5E2+%2B+%28-1%29%5E2+-+4%2A2+%2B+2%2A%28-1%29+=+-5\"
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