document.write( "Question 1026936: Ryn left the museum and drove south. Gab left 3 hours later driving 42 km/h faster in an effort to catch up to him. After 2 hrs, Gab finally caught up. Find Ryn's average speed. \n" ); document.write( "
Algebra.Com's Answer #642205 by MathTherapy(10557)\"\" \"About 
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\n" ); document.write( "Ryn left the museum and drove south. Gab left 3 hours later driving 42 km/h faster in an effort to catch up to him. After 2 hrs, Gab finally caught up. Find Ryn's average speed.
\n" ); document.write( "
Let Ryn’s speed be S
\n" ); document.write( "Then Gab’s speed = S + 42
\n" ); document.write( "As Ryn drove for 5 (3 + 2) hours, and Gab drove for 2 hours, we get the following DISTANCE equation:
\n" ); document.write( "5S = 2(S + 42)
\n" ); document.write( "5S = 2S + 84
\n" ); document.write( "5S – 2S = 84
\n" ); document.write( "3S = 84
\n" ); document.write( "S, or Ryn’s speed = \"84%2F3\", or \"highlight_green%28matrix%281%2C2%2C+28%2C+%22km%2Fh%22%29%29\" \n" ); document.write( "
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