document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1026867>Question 1026867</A>: <I><SPAN STYLE=\"word-break: break-all;\"> F(x)= 3x-2 over x^2+2x-24 - x-3 over x^2-9      \r<BR>\n" );
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document.write( "So far I have (x+6)(x+4) along with (x+3)(x-3) so if the x-3's cancel each other you're left with 3x-2 over (x+6)(x+4)(x+3)...is that the final?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #642178 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=642178\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2 +2x -24 = (x+6) * (x-4)<BR>\n" );
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document.write( "x^2 -9 = (x+3) * (x-3)<BR>\n" );
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document.write( "(3x-2) / ((x+6) * (x-4)) - (x-3) / ((x+3)*(x-3))<BR>\n" );
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document.write( "(3x-2) / ((x+6) * (x-4)) - (1 / (x+3))<BR>\n" );
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document.write( "((3x-2)*(x+3)) - ((x+6)*(x-4)) / ((x+6)*(x-4)*(x+3))<BR>\n" );
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document.write( "(3x^2+7x-6) - (x^2+2x-24)) / ((x+6)*(x-4)*(x+3))<BR>\n" );
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document.write( "F(x) = (2x^2+5x+18) / ((x+6)*(x-4)*(x+3))<BR>\n" );
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