document.write( "Question 1026882: Please assist me on this problem:
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document.write( "A rectangle whose sides are changing in length has a constant area of 100 square meters. Find the length of the rectangle when its width is decreasing at a rate of 1 meter per second and its length is increasing at a rate of 1 meter per second. \n" );
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Algebra.Com's Answer #642173 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! L * W = 100, where L is length and W is width \n" ); document.write( ": \n" ); document.write( "differentiate both sides of = by t which is time \n" ); document.write( ": \n" ); document.write( "L * dW/dt + W * dL/dt = 0 \n" ); document.write( ": \n" ); document.write( "(L * (-0.1)) + (100/L * (0.1)) = 0 \n" ); document.write( ": \n" ); document.write( "-0.1L + (10/L) = 0 \n" ); document.write( ": \n" ); document.write( "-0.1L^2 + 10 = 0 \n" ); document.write( ": \n" ); document.write( "L^2/10 = 10 \n" ); document.write( ": \n" ); document.write( "L^2 = 100 \n" ); document.write( ": \n" ); document.write( "*************** \n" ); document.write( "L = 10 meters \n" ); document.write( "*************** \n" ); document.write( " |