document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1026847>Question 1026847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I find a side length of a polygon if I only know the area?  I specifically need to find the side lengths of a regular pentagon with an area of 49^2 meters. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #642160 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=642160\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I find a side length of a polygon if I only know the area?  I specifically need to find the side lengths of a regular pentagon with an area of 49^2 meters.<BR>\n" );
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document.write( "If you mean 49 sq meters:<BR>\n" );
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document.write( "For any regular polygon:<BR>\n" );
document.write( "Area = ns^2*cot(180/n)/4 where n = # of sides and s = side length<BR>\n" );
document.write( "49 = 5s^2*cot(36)/4<BR>\n" );
document.write( "s^2 = (196/5)*tan(36)<BR>\n" );
document.write( "s =~ 5.3367 meters<BR>\n" );
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document.write( "w/o using the formula:<BR>\n" );
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document.write( "The pentagon is 5 isosceles triangles, each with a central angle of 72 degs and an area of 49/5 sq meters. </SPAN>\n" );
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