document.write( "Question 88371: please I need help\r
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Algebra.Com's Answer #64215 by malakumar_kos@yahoo.com(315)\"\" \"About 
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\n" ); document.write( "The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle\r
\n" ); document.write( "\n" ); document.write( " Let the width of the rectangle be = 2x
\n" ); document.write( " the length of the rectangle = 2x+2 cms
\n" ); document.write( " the perimeter of the rectangle p = 52 cms
\n" ); document.write( " p = 2(length+width)
\n" ); document.write( " 52 = 2(2x+2+2x)
\n" ); document.write( " 52/2 = 4x+2
\n" ); document.write( " 26-2 = 4x
\n" ); document.write( " 24 = 4x
\n" ); document.write( " x = 24/4 = 6
\n" ); document.write( " therefore length of the rectangle = 2.6+2 = 12+2 = 14 cms
\n" ); document.write( " width of the rectangle = 2.6 = 12 cms
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