document.write( "Question 1026848: the length of a rectangle is 7 meters more than four times its width. If the area o the rectangle is 650 square meters, find the length and the width\r
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Algebra.Com's Answer #642145 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
width be x\r
\n" ); document.write( "\n" ); document.write( "length = 4x+7\r
\n" ); document.write( "\n" ); document.write( "Area = 650 m^2\r
\n" ); document.write( "\n" ); document.write( "Area = L *W\r
\n" ); document.write( "\n" ); document.write( "x(4x+7) =650\r
\n" ); document.write( "\n" ); document.write( "4x^2+7x-650=0\r
\n" ); document.write( "\n" ); document.write( "a= 4 , b= 7 , c= -650
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\n" ); document.write( "b^2-4ac= 49 + 10400
\n" ); document.write( "b^2-4ac= 10449
\n" ); document.write( "\"%09sqrt%28%0910449%09%29=%09102.22%09\"
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( -7 + 102.22 )/ 8
\n" ); document.write( "x1= 11.90
\n" ); document.write( "\"x2=%28-b-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x2=( -7 -102.22 ) / 8
\n" ); document.write( "x2= -13.65 \r
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\n" ); document.write( "\n" ); document.write( "ignore negative \r
\n" ); document.write( "\n" ); document.write( "width = 11.8 m\r
\n" ); document.write( "\n" ); document.write( "length = 4*11.9 +7
\n" ); document.write( "=54.6 m\r
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