document.write( "Question 1026853: Five apples and a pear cost $4.67. If an apple cost $0.45, how much does a pear cost? \n" ); document.write( "
Algebra.Com's Answer #642143 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Using only basic math:\r\n" );
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document.write( " $0.45    <-- cost of 1 apple\r\n" );
document.write( "   x 5    <-- number of apples\r\n" );
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document.write( " $2.25    <-- cost of 5 apples\r\n" );
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document.write( " $4.67    <-- cost of 5 apples and 1 pear\r\n" );
document.write( "-$2.25    <-- cost of 5 apples\r\n" );
document.write( "------\r\n" );
document.write( " $2.42    <-- cost of 1 pear\r\n" );
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document.write( "Using algebra:\r\n" );
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document.write( "Five apples and a pear cost $4.67. \r\n" );
document.write( "  |    |     |     |    |     | \r\n" );
document.write( "  5    A     +     P    =    4.67\r\n" );
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document.write( "                 5A + P = 4.67\r\n" );
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document.write( "If an apple cost $0.45, \r\n" );
document.write( "        |    |     |\r\n" );
document.write( "        A    =    0.45 \r\n" );
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document.write( "                      A = 0.45\r\n" );
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document.write( "how much does a pear cost?\r\n" );
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document.write( "Plug (0.45) for A into\r\n" );
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document.write( "                 5A + P = 4.67\r\n" );
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document.write( "            5(0.45) + P = 4.67\r\n" );
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document.write( "Multiply the 5 by the 0.45 and get 2.25 and\r\n" );
document.write( "substitute that for 5(0.45)\r\n" );
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document.write( "               2.25 + P = 4.67\r\n" );
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document.write( "Subtract 2.25 from both sides:\r\n" );
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document.write( "               2.25 + P = 4.67\r\n" );
document.write( "              -2.25      -2.25\r\n" );
document.write( "           ------------------------\r\n" );
document.write( "                      P = 2.42\r\n" );
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document.write( "Answer: $2.42\r\n" );
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document.write( "Edwin
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