document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1026794>Question 1026794</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (a)find the first term of the geometric progression with r=5 in the sum of the first 6 terms is 2604,<BR>\n" );
document.write( "(b)write down the first 6 terms of the geometric progression in (a) above </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #642137 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=642137\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (a)  The sum of the first six terms of a GP is given by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S%5B6%5D+=+g%5B1%5D%28%28r%5E6-1%29%2F%28r-1%29%29 ALIGN=MIDDLE  ALT=\"S%5B6%5D+=+g%5B1%5D%28%28r%5E6-1%29%2F%28r-1%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Since r = 5, the <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S%5B6%5D+=+g%5B1%5D%28%285%5E6-1%29%2F%285-1%29%29+=+3906g%5B1%5D+=+2604 ALIGN=MIDDLE  ALT=\"S%5B6%5D+=+g%5B1%5D%28%285%5E6-1%29%2F%285-1%29%29+=+3906g%5B1%5D+=+2604\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "==> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=g%5B1%5D+=+2%2F3 ALIGN=MIDDLE  ALT=\"g%5B1%5D+=+2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >, the first term of the GP.\r<BR>\n" );
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document.write( "(b)  2/3, 10/3, 50/3, 250/3, 1250/3, 6250/3. </SPAN>\n" );
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