document.write( "Question 1026821: n=3; 2 and 4i are zeros; f (-1)= -102 \n" ); document.write( "
Algebra.Com's Answer #642119 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
n=3; 2 and 4i are zeros; f (-1)= -102
\n" ); document.write( "------
\n" ); document.write( "If you want a polynomial with Real Number coefficients, -4i is also a zero.
\n" ); document.write( "------------------------------------------
\n" ); document.write( "f(x) = a(x-2)(x-4i)(x+4i)
\n" ); document.write( "-----
\n" ); document.write( "f(x) = a(x-2)(x^2+16)
\n" ); document.write( "----
\n" ); document.write( "Use f(-1) = -102 to find \"a\"::
\n" ); document.write( "f(-1) = a(-3)(1+16) = -102
\n" ); document.write( "-----
\n" ); document.write( "-51a = -102
\n" ); document.write( "a = 2
\n" ); document.write( "-------
\n" ); document.write( "Ans: f(x) = 2(x-2)(x^2+16)
\n" ); document.write( "----------------------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "---------------
\n" ); document.write( "
\n" );