document.write( "Question 1026821: n=3; 2 and 4i are zeros; f (-1)= -102 \n" ); document.write( "
Algebra.Com's Answer #642119 by stanbon(75887) ![]() You can put this solution on YOUR website! n=3; 2 and 4i are zeros; f (-1)= -102 \n" ); document.write( "------ \n" ); document.write( "If you want a polynomial with Real Number coefficients, -4i is also a zero. \n" ); document.write( "------------------------------------------ \n" ); document.write( "f(x) = a(x-2)(x-4i)(x+4i) \n" ); document.write( "----- \n" ); document.write( "f(x) = a(x-2)(x^2+16) \n" ); document.write( "---- \n" ); document.write( "Use f(-1) = -102 to find \"a\":: \n" ); document.write( "f(-1) = a(-3)(1+16) = -102 \n" ); document.write( "----- \n" ); document.write( "-51a = -102 \n" ); document.write( "a = 2 \n" ); document.write( "------- \n" ); document.write( "Ans: f(x) = 2(x-2)(x^2+16) \n" ); document.write( "---------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------------- \n" ); document.write( " |