document.write( "Question 1026785: Happy Easter!\r
\n" ); document.write( "\n" ); document.write( "Equations with two radical terms.\r
\n" ); document.write( "\n" ); document.write( "1.) 3 + square root of z-6= square root of z+9\r
\n" ); document.write( "\n" ); document.write( "2.) If g(x)= square root of x + square root of x-5, find any x for which g(x)=5\r
\n" ); document.write( "\n" ); document.write( "3.) square root of a= -1
\n" ); document.write( "

Algebra.Com's Answer #642103 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
1.) \"3%2B+sqrt%28z-6%29+=+sqrt%28z%2B9%29\"
\n" ); document.write( "==> \"9%2B6sqrt%28z-6%29+%2B+z-6+=+z%2B9\" after squaring both sides
\n" ); document.write( "==> \"6sqrt%28z-6%29+=+6\" after simplifying,
\n" ); document.write( "==> \"sqrt%28z-6%29+=+1\"
\n" ); document.write( "==> z-6 = 1 after squaring both sides.
\n" ); document.write( "==> z = 7.
\n" ); document.write( "Substituting z = 7 into the original equation to check if it is extraneous, it easily seen to satisfy the original equation, and so is the only solution.\r
\n" ); document.write( "\n" ); document.write( "2.) \"sqrt%28x%29+%2B+sqrt%28x-5%29+=+5\"
\n" ); document.write( "<==> \"sqrt%28x-5%29+=5-sqrt%28x%29\"
\n" ); document.write( "==> \"x-5+=+25+-+10sqrt%28x%29+%2B+x\" after squaring both sides,
\n" ); document.write( "==> \"10sqrt%28x%29+=+30\" after simplifying,
\n" ); document.write( "==> \"sqrt%28x%29+=+3\" ==> x = 9.
\n" ); document.write( "Substituting x = 9 into the original equation to check if it is extraneous, it easily seen to satisfy the original equation, and so is the only solution.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );