document.write( "Question 1026741: A motorist travelled to a distant city in 2 hours and returned by another route that is 30 miles longer. On the return trip she travelled 10 miles per hour faster and took 6 minutes longer. Find the length of the shorter route. \n" ); document.write( "

Algebra.Com's Answer #642038 by MathTherapy(10810) $\"\"$ $\"About$

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A motorist travelled to a distant city in 2 hours and returned by another route that is 30 miles longer. On the return trip she travelled 10 miles per hour faster and took 6 minutes longer. Find the length of the shorter route.
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Let length of shorter route be D
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document.write( "Then length of longer route = D + 30
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document.write( "Outgoing time: 2 hours, and return time =  ----->  ----->  hrs 
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document.write( "We then get the following SPEED equation: 
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document.write( "21D = 2(10D + 300) - 420 -------- Multiplying by LCD, 42
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document.write( "21D = 20D + 600 – 420
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document.write( "21D – 20D = 180
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document.write( "D, or length of shorter route =  \n" );
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