document.write( "Question 1026729: Prove the proposition |z|=1 if {(1+z)/(1-z)} is purely imaginary. Please help. \n" ); document.write( "
Algebra.Com's Answer #642026 by robertb(5830)\"\" \"About 
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\"%281%2Bz%29%2F%281-z%29\" purely imaginary implies that \"%281%2Bz%29%2F%281-z%29+=+i%2Aalpha\" for some real number \"alpha\".
\n" ); document.write( "Now let z = a+ib for real numbers a, b.\r
\n" ); document.write( "\n" ); document.write( "==> \"%281%2B+a+%2B+ib%29%2F%281-a+-+ib%29+=+i%2Aalpha\"
\n" ); document.write( "<==> \"1%2B+a+%2B+ib=%281-a+-+ib%29%2Ai%2Aalpha\"
\n" ); document.write( "==> \"1%2B+a+%2B+ib=i%2Aalpha-a%2Ai%2Aalpha+-+ib%2Ai%2Aalpha\"
\n" ); document.write( "<==> \"1%2B+a+%2B+ib=i%2Aalpha-a%2Ai%2Aalpha+%2B+b%2Aalpha\"
\n" ); document.write( "<==> \"%281%2Ba%29%2Bib+=+b%2Aalpha%2B+alpha%2A%281-a%29i\"
\n" ); document.write( "==> \"1%2Ba=b%2Aalpha\" and \"b+=+alpha%2A%281-a%29\".
\n" ); document.write( "These equations become a system of linear equations in a and b.
\n" ); document.write( "Solving for a and b gives
\n" ); document.write( "\"a+=+%28-1%2Balpha%5E2%29%2F%281%2Balpha%5E2%29\" and \"b+=+%282alpha%29%2F%281%2Balpha%5E2%29\".\r
\n" ); document.write( "\n" ); document.write( "Now .
\n" ); document.write( "=, and the statement is proved.\r
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