document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1026722>Question 1026722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the value. (Link to the question below)<BR>\n" );
document.write( "https://gyazo.com/bcdf8f7350b80bdf7844a55a42d13991 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #642001 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=642001\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=60x/(1+0.625x)<BR>\n" );
document.write( "as x increases to infinity, positive or negative, the denominator becomes 0.625x for all practical purposes, since the addition of 1 does not change anything significantly.  The sign of the numerator and the denominator will be + or -.<BR>\n" );
document.write( "y=60x/0.625x<BR>\n" );
document.write( "y=60(5/8)<BR>\n" );
document.write( "y=96, horizontal asymptote.<BR>\n" );
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