document.write( "Question 1026666: Jill is 10 years younger than Brian. In 5 years, Jill will be two-thirds of Brian's age. how old will Jill be seven years from now? \n" ); document.write( "
Algebra.Com's Answer #641948 by ankor@dixie-net.com(22740)\"\" \"About 
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Jill is 10 years younger than Brian.
\n" ); document.write( "j = b - 10
\n" ); document.write( ":
\n" ); document.write( " In 5 years, Jill will be two-thirds of Brian's age.
\n" ); document.write( "j + 5 = \"2%2F3\"(b+5)
\n" ); document.write( "get rid of the fraction, multiply both sides by 3
\n" ); document.write( "3(j+5) = 2(b+5)
\n" ); document.write( "3j + 15 = 2b + 10
\n" ); document.write( "3j = 2b + 10 - 15
\n" ); document.write( "3j = 2b - 5
\n" ); document.write( "Replace j with (b-10) from the first statement
\n" ); document.write( "3(b-10) = 2b - 5
\n" ); document.write( "3b - 30 = 2b - 5
\n" ); document.write( "3b - 2b = -5 + 30
\n" ); document.write( "b = 25 yrs is Brian's age
\n" ); document.write( "then
\n" ); document.write( "j = 25 - 10
\n" ); document.write( "j = 15 yrs is Jill's age
\n" ); document.write( ":
\n" ); document.write( " how old will Jill be seven years from now?
\n" ); document.write( "I'll let you figure this out \n" ); document.write( "
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