document.write( "Question 1026655: When the original price of an item is increased by a certain rate, the increased price is P3100. When the original price is decreased by the same rate, the decreased priced is P 1900. What is the original price of the item? \n" ); document.write( "
Algebra.Com's Answer #641926 by robertb(5830)\"\" \"About 
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Let p = original price of the item, and r = rate of increase/decrease.\r
\n" ); document.write( "\n" ); document.write( "==> P(1+r) = 3100 and P(1-r) = 1900, as per given information.\r
\n" ); document.write( "\n" ); document.write( "Divide the first equation by the second equation (divide corresponding sides.)\r
\n" ); document.write( "\n" ); document.write( "==> \"%281%2Br%29%2F%281-r%29+=+31%2F19\"
\n" ); document.write( "==> \"19+%2B+19r+=+31+-+31r\"
\n" ); document.write( "==> \"50r+=+12\" ==> r = 0.24\r
\n" ); document.write( "\n" ); document.write( "==> P(1.24) = 3100 ==> \"P+=+3100%2F1.24+=+2500\" after substituting into the first equation.\r
\n" ); document.write( "\n" ); document.write( "Therefore, P = P2,500, the original price of the item.
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