document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1026643>Question 1026643</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the function f(x) = (x-13)^2 , where x is less than or equal to 13 find the domain and inverse  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #641900 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=641900\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> That is the left branch of f(x).  The corresponding inverse will the the lower branch.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28y-13%29%5E2=x ALIGN=MIDDLE  ALT=\"%28y-13%29%5E2=x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-13=0%2B-+sqrt%28x%29 ALIGN=MIDDLE  ALT=\"y-13=0%2B-+sqrt%28x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "LOWER BRANCH IS <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=13-sqrt%28x%29 ALIGN=MIDDLE  ALT=\"y=13-sqrt%28x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and better notation from here could be  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%5E%28-1%29%28x%29=13-sqrt%28x%29 ALIGN=MIDDLE  ALT=\"f%5E%28-1%29%28x%29=13-sqrt%28x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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