document.write( "Question 12603: I know the result to this problem, but am having a hard time finding the equation that works for it. I spent 2 hours on it last night with no luck, can you help me please? The question is as follows:\r
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document.write( "Abby has 37 coins, consisting only of dimes and quarters, woth $7.45. How many dimes and how many quarters does she have?\r
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document.write( "I know that she has 25 quarters and 12 dimes, but that is form simple math.\r
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document.write( "Thanks for the help!!\r
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document.write( "Capesch \n" );
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Algebra.Com's Answer #6419 by AdolphousC(70)  You can put this solution on YOUR website! You need to set this up as a system of linear equations, \n" );
document.write( "Define your varibles, Let D = # of Dimes, and Q = # of Quarters \n" );
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document.write( "First Equation is the one where you actually just count the coins... \n" );
document.write( "D + Q = 37\r \n" );
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document.write( "Now, adding the value of the coins, here is where you count the money, \n" );
document.write( "Dimes are worth 10 cents and quarters 25... \n" );
document.write( ".1D + .25Q = 7.45 \n" );
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document.write( "D + Q = 37 \n" );
document.write( ".1D + .25Q = 7.45 \n" );
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document.write( "Now you have a simple system, I will multiply the top by .1\r \n" );
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document.write( ".1(D + Q = 37) \n" );
document.write( ".1D + .25Q = 7.45 \n" );
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document.write( ".1D + .1Q = 3.7 \n" );
document.write( ".1D + .25Q = 7.45 Now subtract the two equations \n" );
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document.write( "-.15Q = -3.75 Divide both sides by -.15 \n" );
document.write( "Q = 25\r \n" );
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document.write( "Now substitute into your original equations \n" );
document.write( "D + Q = 37 \n" );
document.write( "D + 25 = 37 Subtract \n" );
document.write( "D = 12\r \n" );
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document.write( "So she indeed has 25 Quarters and 12 Dimes\r \n" );
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