document.write( "Question 1026596: Could someone please check my work? \"Find the inverse of f(x)=sqrt x-h. Identify the domain and the range of the inverse.\" I think I did the problem correctly, and got y=x^2+ h, then f^-1(x)=x^2 + h for the inverse? The domain and range I'm not sure about. Domain of inverse= (0, infinity). Range of inverse=(h, infinity). It also seems like I should write the domain and range with a less than or equal to sign or something? I appreciate any help and thank you for your time! \n" ); document.write( "
Algebra.Com's Answer #641847 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
\"Find the inverse of f(x)=sqrt(x-h). Identify the domain and the range of the inverse.\"
\n" ); document.write( "---
\n" ); document.write( "y = sqrt(x-h)
\n" ); document.write( "Domain:: x >= h
\n" ); document.write( "Range:: All Real Numbers >= 0\r
\n" ); document.write( "\n" ); document.write( "----
\n" ); document.write( "1st:: Interchange x and y::
\n" ); document.write( "x = sqrt(y-h)
\n" ); document.write( "2nd:: Solve for \"y\"::
\n" ); document.write( "y-h = x^2
\n" ); document.write( "y = x^2+h
\n" ); document.write( "-----------------------
\n" ); document.write( "Domain of inverse:: All Real Numbers >= 0
\n" ); document.write( "Range:: y >= h
\n" ); document.write( "-----------------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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