document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1026587>Question 1026587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A metal worker has a metal alloy that 30% copper and another one is 55% copper. how many kilograms of each alloy should the metalworker combine to make 50kg of a 50% copper alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #641838 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=641838\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A metal worker has a metal alloy that 30% copper and another one is 55% copper. how many kilograms of each alloy should the metalworker combine to make 50kg of a 50% copper alloy? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "copper + copper = copper<BR>\n" );
document.write( "0.30x + 0.55(50-x) = 0.50*50 kg<BR>\n" );
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document.write( "30x + 55*50 - 55x = 50*50<BR>\n" );
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document.write( "-25x = -5*50<BR>\n" );
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document.write( "x = 10 kg (amt. of 30% needed)<BR>\n" );
document.write( "50-x = 40 kg (amt. of 55% needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "----------- </SPAN>\n" );
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