document.write( "Question 1026553: A service station checks Mr. Gittleboro's radiator and finds it contains only 30% antifreeze. If the radiator holds 10 quarts and is full, how much be drained off and replaced with pure antifreeze in order to bring it up to a required 50% anti freeze? \n" ); document.write( "
Algebra.Com's Answer #641787 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Assume we have to removae x quarts of antifreeze from the radiator and add 100% one\r
\n" ); document.write( "\n" ); document.write( "Antifreeze
\n" ); document.write( " percent ---------------- quantity
\n" ); document.write( "Antifreeze pure 100.00% ---------------- x quarts
\n" ); document.write( "Antifreeze I 30.00% ------ 10 - x quarts
\n" ); document.write( "Mixture 50.00% ---------------- 10
\n" ); document.write( " 10
\n" ); document.write( "100.00% x + 30.00% ( 10 - x ) = 50.00% * 10
\n" ); document.write( "100 x + 30 ( 10 - x ) = 500
\n" ); document.write( "100 x + 300 - 30 x = 500
\n" ); document.write( "100 x - 30 x = 500 - -300
\n" ); document.write( "70 x = 200
\n" ); document.write( "/ 70
\n" ); document.write( " x = 2.86 quarts 100.00% Antifreeze pure
\n" ); document.write( " 7.14 quarts 30.00% Antifreeze I
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "
\n" );