document.write( "Question 1026548: julie is three times as old as her son. in 12 years, Julie's age will be one year less than twice her son's age. how old is julie now? \n" ); document.write( "

Algebra.Com's Answer #641779 by ikleyn(52798) $\"\"$ $\"About$

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\n" ); document.write( "Julie is three times as old as her son. In 12 years, Julie's age will be one year less than twice her son's age. How old is Julie now?
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document.write( "J = 3s,              (1)      (Julie is three times as old as her son.)\r\n" );
document.write( "J+12 = 2(s+12) - 1.  (2)      (In 12 years, Julie's age will be one year less than twice her son's age.)\r\n" );
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document.write( "Here J = Julie's age now, s = Julie' son age now.\r\n" );
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document.write( "Substitute J = 3s from (1) into (2). You will get single equation for s:\r\n" );
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document.write( "3s + 12 = 2(s+12) - 1,   or\r\n" );
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document.write( "3s + 12 = 2s + 24 - 1,   or\r\n" );
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document.write( "s = 24 - 1 - 12 = 11.\r\n" );
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document.write( "Thus Julie' son is 11 years now. \r\n" );
document.write( "Then Julie is 3*s = 33 years old now.\r\n" );
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document.write( "Solved.\r\n" );
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