document.write( "Question 1026492: Jolene invests her savings in two bank accounts, one paying 4% and the other paying 11% simple interest per year. She puts twice as much in the lower-yielding account because it is less risky. Her annual interest is 3021 dollars. How much did she invest at each rate?
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document.write( "Amount invested at 4% interest is
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document.write( "Amount invested at 11% interest is \n" );
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Algebra.Com's Answer #641750 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Amount @ 11.00% x \n" ); document.write( "Amount @ 4.00% 2 x \n" ); document.write( "Total interest earned = 3,021.00 \n" ); document.write( " \n" ); document.write( "11.00% x+ 4.00% ( 2 x)= 3021 \n" ); document.write( "11.00% x+ 4.00% * 2 x= 3021 \n" ); document.write( "11.00% x+ 8%x =3021 \n" ); document.write( "multiply by 100 \n" ); document.write( "11.00 x+ 8 x = 302100 \n" ); document.write( "19 x = 302100 \n" ); document.write( " x= 15900 Amount @ 11.00% \n" ); document.write( " = \n" ); document.write( "Amount @ 4.00% = 2 * 15900 \n" ); document.write( " = 31800 \n" ); document.write( " \n" ); document.write( " |