document.write( "Question 88347: Please help me solve this problem:\r
\n" ); document.write( "\n" ); document.write( "EXPONENTS:
\n" ); document.write( "Simplify.\r
\n" ); document.write( "\n" ); document.write( "#24. \"7%5E%284n-5%29%287%5E%282n%2B3%29%29%5E3=%287%5E%284-6n%29%29%5E4\"\r
\n" ); document.write( "\n" ); document.write( "Please and Thank you!!!!
\n" ); document.write( "

Algebra.Com's Answer #64173 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given:
\n" ); document.write( ".
\n" ); document.write( "\"%287%5E%284n-5%29%29%2A%287%5E%282n%2B3%29%29%5E3=%287%5E%284-6n%29%29%5E4\"
\n" ); document.write( ".
\n" ); document.write( "First, note that all the bases are 7, so the rules that depend on the bases being common can
\n" ); document.write( "be used.
\n" ); document.write( ".
\n" ); document.write( "Next note that two of the terms have exponents. The applicable rule for this this is:
\n" ); document.write( ".
\n" ); document.write( "\"%28x%5Ea%29%5Eb+=+x%5E%28a%2Ab%29\"
\n" ); document.write( ".
\n" ); document.write( "for the term \"%287%5E%282n+%2B+3%29%29%5E3\" you have x = 7, a = 2n +3, and b = 3. Substituting
\n" ); document.write( "these values into the rule results in:
\n" ); document.write( ".
\n" ); document.write( "\"%287%5E%282n%2B3%29%29%5E3+=+7%5E%28%282n%2B3%29%2A3%29+=+7%5E%286n+%2B+9%29\"
\n" ); document.write( ".
\n" ); document.write( "Similarly, the other term of the original problem that also can be simplified using the
\n" ); document.write( "power rule is:
\n" ); document.write( ".
\n" ); document.write( "\"%287%5E%284-6n%29%29%5E4\"
\n" ); document.write( ".
\n" ); document.write( "For this term x = 7, a = (4 - 6n), and b = 3. Substituting these values into the power rule
\n" ); document.write( "results in:
\n" ); document.write( ".
\n" ); document.write( "\"%287%5E%284-6n%29%29%5E4+=+7%5E%28%284-6n%29%2A4%29+=+7%5E%2816-24n%29\"
\n" ); document.write( ".
\n" ); document.write( "Substituting the two simplifications into the original given problem results in it becoming:
\n" ); document.write( ".
\n" ); document.write( "\"7%5E%284n-5%29%2A7%5E%286n+%2B+9%29=7%5E%2816-24n%29\"
\n" ); document.write( ".
\n" ); document.write( "Now you can apply the rule for two terms of a common base, each term raised to an exponent,
\n" ); document.write( "when the two terms are multiplied. This rule states that the product is the common base
\n" ); document.write( "raised to the sum of the exponents. In equation form this is:
\n" ); document.write( ".
\n" ); document.write( "\"x%5Ea+%2A+x%5Eb+=+x%5E%28a%2Bb%29\"
\n" ); document.write( ".
\n" ); document.write( "On the left side of the equation we have developed there are two terms that are multiplied.
\n" ); document.write( "In this product x = 7, a = 4n - 5, and b = 6n + 9. When you substitute these values into
\n" ); document.write( "the left side of the equation you get:
\n" ); document.write( ".
\n" ); document.write( "
\n" ); document.write( ".
\n" ); document.write( "This becomes the left side of the equation. The equation becomes:
\n" ); document.write( ".
\n" ); document.write( "\"7%5E%2810n+%2B+4%29=+7%5E%2816-24n%29\"
\n" ); document.write( ".
\n" ); document.write( "Note that since the bases on the left and right sides are both the same ... 7 ... for
\n" ); document.write( "the equation to be true, the two exponents have to be the same. So therefore you can say:
\n" ); document.write( ".
\n" ); document.write( "\"10n+%2B+4+=+16+-+24n\"
\n" ); document.write( ".
\n" ); document.write( "We can solve this equation by getting all the terms containing n on one side of the equation
\n" ); document.write( "and all the terms that are just numbers on the other side. Start by adding +24n to both sides.
\n" ); document.write( "this makes the equation become:
\n" ); document.write( ".
\n" ); document.write( "\"24n+%2B+10n+%2B+4+=+16+-+24n+%2B+24n\"
\n" ); document.write( ".
\n" ); document.write( "combining the terms containing n reduces the equation to:
\n" ); document.write( ".
\n" ); document.write( "\"34n+%2B+4+=+16\"
\n" ); document.write( ".
\n" ); document.write( "Next add -4 to both sides to eliminate the +4 on the left side. This makes the equation:
\n" ); document.write( ".
\n" ); document.write( "\"34n+=+12\"
\n" ); document.write( ".
\n" ); document.write( "Finally, solve for n by dividing both sides by 34 to get:
\n" ); document.write( ".
\n" ); document.write( "\"n+=+12%2F34+=+6%2F17\"
\n" ); document.write( ".
\n" ); document.write( "Hope this helps you to see your way through the problem.
\n" ); document.write( "
\n" );