document.write( "Question 1026445: Emp 1 : mon: present ,tue: present ,wed:present ,thur: present ,fri :present .sat:week off ,sun: weekoff\r
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document.write( "Emp 2 : mon: week off ,tue: present ,wed:present ,thur:absent ,fri :present .sat:week off ,sun: weekoff\r
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document.write( "Emp 3 : mon: absent ,tue: absent ,wed:present ,thur: present ,fri :present .sat:absent ,sun: weekoff\r
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document.write( "Emp 4 : mon:Week-Off ,tue:present ,wed:present ,thur:absent ,fri :present .sat:present ,sun: present \r
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document.write( "Emp 5 : mon:absent ,tue:absent ,wed:absent ,thur:absent ,fri :present .sat:present ,sun: present \r
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document.write( "Emp 6 : mon:Week-Off ,tue:Week-Off ,wed:Week-Off ,thur:presesnt ,fri :present .sat:present ,sun: absent\r
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document.write( "I have 6 employee in my organization :emp 1 to emp 6 ,\r
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document.write( "I have their daily attendance record : Present(p) ,Absent(a) ,Week-off (-)\r
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document.write( "actual working days (AWD) differ for each employee ,some may work for 5 days in a week and some 7 days in a week (week-off not considered part of working day)\r
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document.write( "Now, I want to calculate average attendance in that week \r
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document.write( "case 1 : add all the present attendance data :\r
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document.write( " like : emp 1 present for 5 days \r
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document.write( "emp 2 present for 3 days , and so on for all 6 emp \r
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document.write( "the sum of present attendance is 22 ,\r
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document.write( "now what should i divide this number by , if i divide 22 by 7 working days , then it would not give me a accurate number as emp1 has worked for only 5 days , so it would give me a false average as actual working days (AWD) differ for each employee , so how to get average\r
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document.write( "Case 2 :\r
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document.write( "can i calculate percentage :\r
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document.write( "emp1 Present for 5 days actual working days 5 ,so attendance :100 %\r
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document.write( "likewise : emp2 attendance: 75%
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document.write( "emp 3 attendance 50%
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document.write( "emp 4: 83% ,emp5=43%, emp 6=75%\r
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document.write( "so average of all attendance percentage = 71% \r
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document.write( "so tell me ,does this number provide an accurate deception of attendance \r
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document.write( "or is there a another solution , \r
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document.write( "tip : kindly enter data in excel for understanding , substitute :
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document.write( "present = p
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document.write( "absent =a
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document.write( "week off = \"-\"
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document.write( "actual working days =AWD\r
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Algebra.Com's Answer #641705 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! Case 1) Average attendance in that week \n" ); document.write( "Emp 1 is 5/5 \n" ); document.write( "Emp 2 is 3/4 \n" ); document.write( "Emp 3 is 3/6 \n" ); document.write( "Emp 4 is 5/6 \n" ); document.write( "Emp 5 is 3/7 \n" ); document.write( "Emp 6 is 3/4 \n" ); document.write( "Average attendance in that week is 22/32 = 0.6875 \n" ); document.write( ": \n" ); document.write( "Case 2) Attendance using % \n" ); document.write( "Emp 1 is 1.00 \n" ); document.write( "Emp 2 is 0.75 \n" ); document.write( "Emp 3 is 0.50 \n" ); document.write( "Emp 4 is 0.833333333 \n" ); document.write( "Emp 5 is 0.428571429 \n" ); document.write( "Emp 6 is 0.75 \n" ); document.write( "Sum the %'s and divide by 6 is 4.2619 / 6 = 0.7103166 \n" ); document.write( ": \n" ); document.write( "Case 2 is on a per employee basis \n" ); document.write( ": \n" ); document.write( "Case 1 tells us that out of 32 employee work days we had 22 employee work days \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |