document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1026451>Question 1026451</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A box contain 6 white, 5 red and 4 black pencils. Fin the probability of getting at least two red pencils if four pencils are drawn<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #641698 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=641698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Probability(X > = 2) = 1 - (Pr(X=0) + Pr(X=1))<BR>\n" );
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document.write( "This says the Probability(Pr) that at least 2 pencils picked without replacement is equal to 1 minus the probability of no red pencils picked plus the probability that 1 red pencil is picked<BR>\n" );
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document.write( "Pr(X=0) = (10/15)*(9/14)*(8/13)*(7/12) = 0.153846154<BR>\n" );
document.write( "Pr(X=1) = (5/15)*(10/14)*(9/13)*(8/12) = 0.10989011<BR>\n" );
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document.write( "Pr(X > = 2) = 1 - (0.153846154 + 0.10989011)<BR>\n" );
document.write( "Pr(X > = 2) = 1 - 0.263736264 = 0.736263736<BR>\n" );
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document.write( "Pr(X > = 2) is approx 0.74<BR>\n" );
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