document.write( "Question 1026423: a contractor took a work to complete in 17 days by 9 employee. in 8 days 2/5 work was finished by 9 employee. how many extra employee are required to finish the remaining work on time? \n" ); document.write( "
Algebra.Com's Answer #641696 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a contractor took a work to complete in 17 days by 9 employee. \n" ); document.write( " in 8 days 2/5 work was finished by 9 employee. \n" ); document.write( " how many extra employee are required to finish the remaining work on time? \n" ); document.write( ": \n" ); document.write( "We know 9 men did 2/5 of the work \n" ); document.write( "How many men are required to do the remaining 3/5 of the work \n" ); document.write( ": \n" ); document.write( "let the completed job = 1 \n" ); document.write( "each man did \n" ); document.write( ": \n" ); document.write( "let m = the additional men required to complete the remaining 3/5 of the job in 9 more days \n" ); document.write( ": \n" ); document.write( "the shared work equation, each man working 9 days \n" ); document.write( "9* \n" ); document.write( "multiply equation by 180 \n" ); document.write( "81 + 9m = 36(3) \n" ); document.write( "9m = 108 - 81 \n" ); document.write( "9m = 27 \n" ); document.write( "m = 27/9 \n" ); document.write( "m = 3 more men required \n" ); document.write( " \n" ); document.write( " |