document.write( "Question 1026423: a contractor took a work to complete in 17 days by 9 employee. in 8 days 2/5 work was finished by 9 employee. how many extra employee are required to finish the remaining work on time? \n" ); document.write( "
Algebra.Com's Answer #641696 by ankor@dixie-net.com(22740)\"\" \"About 
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a contractor took a work to complete in 17 days by 9 employee.
\n" ); document.write( " in 8 days 2/5 work was finished by 9 employee.
\n" ); document.write( " how many extra employee are required to finish the remaining work on time?
\n" ); document.write( ":
\n" ); document.write( "We know 9 men did 2/5 of the work
\n" ); document.write( "How many men are required to do the remaining 3/5 of the work
\n" ); document.write( ":
\n" ); document.write( "let the completed job = 1
\n" ); document.write( "each man did \"1%2F8\" * \"1%2F9\" * \"2%2F5\" = \"2%2F360\" = \"1%2F180\" of the job per day
\n" ); document.write( ":
\n" ); document.write( "let m = the additional men required to complete the remaining 3/5 of the job in 9 more days
\n" ); document.write( ":
\n" ); document.write( "the shared work equation, each man working 9 days
\n" ); document.write( "9*\"9%2F180\" + 9*\"m%2F180\" = \"3%2F5\"
\n" ); document.write( "multiply equation by 180
\n" ); document.write( "81 + 9m = 36(3)
\n" ); document.write( "9m = 108 - 81
\n" ); document.write( "9m = 27
\n" ); document.write( "m = 27/9
\n" ); document.write( "m = 3 more men required
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