document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=88343>Question 88343</A>: <I><SPAN STYLE=\"word-break: break-all;\"> word problem delimma tickets for a play cost $12 for an adult and $8 for an child If 130 tickets were sold and the total receipts were 1160 how many of each ticket weree sold. Ok if x= the adult tickets and c= the child tickets do I go x+ c = 130 and then go 12x + 8c==1160 then divide both sidec by 8 to get the child ticket </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64169 by </B><A HREF=/tutors/aboutme.mpl?userid=rossiv53><B>rossiv53(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rossiv53><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64169\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Lets begin by assigning a variable to one of the ticket values.<BR>\n" );
document.write( "x = number of adult tickets sold<BR>\n" );
document.write( "Since there were a total of 130 tickets sold, the amount of children's tickets sold can be expressed as (130-x)\r<BR>\n" );
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document.write( "Now you can set up your equation<BR>\n" );
document.write( "12x+8(130-x) = 1160<BR>\n" );
document.write( "12x+1040-8x = 1160<BR>\n" );
document.write( "4x+1040 = 1160<BR>\n" );
document.write( "4x+1040-1040 = 1160-1040<BR>\n" );
document.write( "4x = 120<BR>\n" );
document.write( "x = 30\r<BR>\n" );
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document.write( "So, 30 adult tickets were sold and 100 children's tickets were sold\r<BR>\n" );
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document.write( "Good luck! </SPAN>\n" );
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