document.write( "Question 88349This question is from textbook Intermediate Algebra Graph and models
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document.write( ": The A train goes 12mph slower than the E train. The A train travels 230 mi in the same time that the E train travels 290 mil. Find the speed of each train.\r
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document.write( "I am lost in how to set up the equation to be able to solve to find the speed of each train.\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #64163 by rossiv53(27) ![]() You can put this solution on YOUR website! Use formula for time \n" ); document.write( "Since each train travels for the same time, we'll set them equal to each other. \n" ); document.write( "rate for E train = x \n" ); document.write( "rate for A train = (x-12) since it travels 12mph slower. \n" ); document.write( "your equation \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "230x=290(x-12) \n" ); document.write( "230x=-290x-3480 \n" ); document.write( "-60x=-3480 \n" ); document.write( "x=58\r \n" ); document.write( "\n" ); document.write( "So, rate for E train is 58mph and since the A train is 12mph slower, its rate is 46mph.\r \n" ); document.write( "\n" ); document.write( "Good luck! \n" ); document.write( " |