document.write( "Question 88349This question is from textbook Intermediate Algebra Graph and models
\n" ); document.write( ": The A train goes 12mph slower than the E train. The A train travels 230 mi in the same time that the E train travels 290 mil. Find the speed of each train.\r
\n" ); document.write( "\n" ); document.write( "I am lost in how to set up the equation to be able to solve to find the speed of each train.\r
\n" ); document.write( "\n" ); document.write( "Thank you
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Algebra.Com's Answer #64163 by rossiv53(27)\"\" \"About 
You can put this solution on YOUR website!
Use formula for time \"time=distance%2Frate\"
\n" ); document.write( "Since each train travels for the same time, we'll set them equal to each other.
\n" ); document.write( "rate for E train = x
\n" ); document.write( "rate for A train = (x-12) since it travels 12mph slower.
\n" ); document.write( "your equation
\n" ); document.write( "\"230%2F%28x-12%29=290%2Fx\"
\n" ); document.write( "cross multiply
\n" ); document.write( "230x=290(x-12)
\n" ); document.write( "230x=-290x-3480
\n" ); document.write( "-60x=-3480
\n" ); document.write( "x=58\r
\n" ); document.write( "\n" ); document.write( "So, rate for E train is 58mph and since the A train is 12mph slower, its rate is 46mph.\r
\n" ); document.write( "\n" ); document.write( "Good luck!
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