document.write( "Question 1026389: Jen butler has been pricing speed pass train fares for a group trip to new york. Three adults and four children must pay ree adults and four children must pay $89. Two adults and tree children must pay $63. Find the price of the adult ticket and the price of the childs ticket. \n" ); document.write( "
Algebra.Com's Answer #641627 by addingup(3677)\"\" \"About 
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3a+4c = 89 multiply times 2
\n" ); document.write( "2a+3c = 63 multiply times 3
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\n" ); document.write( "Multiply, then subtract
\n" ); document.write( "6a+8c = 178
\n" ); document.write( "-
\n" ); document.write( "6a+9c = 189
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\n" ); document.write( ". -c = -11 divide both sides by -1
\n" ); document.write( "c = 11 This is the cost of a child's ticket. And the adult:
\n" ); document.write( "3a+4(11) = 89
\n" ); document.write( "3a+44 = 89
\n" ); document.write( "3a = 45
\n" ); document.write( "a = 15 is the cost of an adult ticket
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\n" ); document.write( "Check:
\n" ); document.write( "3 adults*15 = 45
\n" ); document.write( "4 children*11= 44
\n" ); document.write( "Total. . . . 89 Correct
\n" ); document.write( "And:
\n" ); document.write( "2 adults*15 = 30
\n" ); document.write( "3 children*11= 33
\n" ); document.write( "Total. . . . . 63 Also correct
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