document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1026358>Question 1026358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with the following word problem:<BR>\n" );
document.write( "The perimeter of a rectangle is 64 cm.\r<BR>\n" );
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document.write( "(a)  <BR>\n" );
document.write( "If the width of the rectangle is x cm, give a formula for y, the height of the rectangle in cm, in terms of x.\r<BR>\n" );
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document.write( "For this one I got y=32-x, but the answer is needed for part b so I thought I should include it.\r<BR>\n" );
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document.write( "(b)  <BR>\n" );
document.write( "Using your answer in part (a), give a formula for A, the area in cm^2, in terms of the width x.\r<BR>\n" );
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document.write( "For this one, I tried to substitute the formula for y into the equation for the perimeter: 2x+2y=64. This didn't work because when I substituted that formula into the equation, the equation didn't allow me to solve for y because it zeroed out.\r<BR>\n" );
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document.write( "(c)  <BR>\n" );
document.write( "Find the lengths of the sides of the rectangle giving the maximum area. What is the maximum area?\r<BR>\n" );
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document.write( "For this one, I couldn't do it since the substitution in the previous problem didn't help. I also don't understand what maximum area means. <BR>\n" );
document.write( "Thank you for the help and your time :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #641598 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=641598\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) y = 32-x is correct<BR>\n" );
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document.write( "b) Area(A) = x * y, then<BR>\n" );
document.write( "A = x * (32-x) = 32 -x^2<BR>\n" );
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document.write( "c) b) is the formula of a parabola that curves downward, so the maximum area will be y coordinate of the parabola's vertex.<BR>\n" );
document.write( "The x is -b/2a which is -32 / (2 * (-1)) = 16 and y is 32 - 16 = 16<BR>\n" );
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document.write( "x = 16 cm<BR>\n" );
document.write( "y = 16 cm<BR>\n" );
document.write( "Max area is 16^2 = 256 cm^2<BR>\n" );
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document.write( " </SPAN>\n" );
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