document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1026262>Question 1026262</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the formula S = &#8730;(30Df ) to determine the distance required for a car to skid to a stop. (S is the car's in miles per hour, D is the length of the skid marks in feet, and f is the coefficient of friction between the tires and the road.)\r<BR>\n" );
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document.write( "f = 0.8 ; S = 45 mi/hr\r<BR>\n" );
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document.write( "NOTE:\r<BR>\n" );
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document.write( "&#8730;(30Df ) is a square root of 30Df </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #641596 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=641596\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S = sqrt(30DF)<BR>\n" );
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document.write( "square both sides of =<BR>\n" );
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document.write( "S^2 = 30DF<BR>\n" );
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document.write( "D = S^2 / 30F<BR>\n" );
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document.write( "D = 45^2 / (30*0.8) = 84.375 feet </SPAN>\n" );
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