document.write( "Question 1026343: Two boys decided to buy a computer. The second boy had 5/6 of the money the first had. The first boy had 7/8 of the price of the computer. Together they had $696.00 more than they need to pay. What was the price for the computer? \n" ); document.write( "
Algebra.Com's Answer #641587 by stanbon(75887)\"\" \"About 
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Two boys decided to buy a computer. The second boy had 5/6 of the money the first had. The first boy had 7/8 of the price of the computer. Together they had $696.00 more than they need to pay. What was the price for the computer?
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\n" ); document.write( "Equations:
\n" ); document.write( "s = (5/6)f
\n" ); document.write( "f = (7/8)c
\n" ); document.write( "f + s = c + 696
\n" ); document.write( "-------
\n" ); document.write( "Substitute for f and for s ; solve for \"c\"::
\n" ); document.write( "(7/8)c + (5/6)(7/8)c + c = 696
\n" ); document.write( "------
\n" ); document.write( "[1 + (5/6)](7/8)c + c = 696
\n" ); document.write( "(11/6)(7/8)c = 696
\n" ); document.write( "(77/48)c = 696
\n" ); document.write( "computer = 48*696/77 = $433.87
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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