document.write( "Question 88331: Identify the axis of symmetry, create a suitable table of values, then sketch the graph (including the axis of symmetry).\r
\n" ); document.write( "\n" ); document.write( "y = –x^2 + 3x – 3\r
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Algebra.Com's Answer #64154 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Completing the Square to Get a Quadratic into Vertex Form

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\n" ); document.write( " \"y=-1+x%5E2%2B3+x-3\" Start with the given equation
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\n" ); document.write( " \"y%2B3=-1+x%5E2%2B3+x\" Add \"3\" to both sides
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\n" ); document.write( " \"y%2B3=-1%28x%5E2-3x%29\" Factor out the leading coefficient \"-1\"
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\n" ); document.write( " Take half of the x coefficient \"-3\" to get \"-3%2F2\" (ie \"%281%2F2%29%28-3%29=-3%2F2\").
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\n" ); document.write( " Now square \"-3%2F2\" to get \"9%2F4\" (ie \"%28-3%2F2%29%5E2=%28-3%2F2%29%28-3%2F2%29=9%2F4\")
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\n" ); document.write( " \"y%2B3=-1%28x%5E2-3x%2B9%2F4-9%2F4%29\" Now add and subtract this value inside the parenthesis. Doing both the addition and subtraction of \"9%2F4\" does not change the equation
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\n" ); document.write( " \"y%2B3=-1%28%28x-3%2F2%29%5E2-9%2F4%29\" Now factor \"x%5E2-3x%2B9%2F4\" to get \"%28x-3%2F2%29%5E2\"
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\n" ); document.write( " \"y%2B3=-1%28x-3%2F2%29%5E2%2B1%289%2F4%29\" Distribute
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\n" ); document.write( " \"y%2B3=-1%28x-3%2F2%29%5E2%2B9%2F4\" Multiply
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\n" ); document.write( " \"y=-1%28x-3%2F2%29%5E2%2B9%2F4-3\" Now add \"%2B3\" to both sides to isolate y
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\n" ); document.write( " \"y=-1%28x-3%2F2%29%5E2-3%2F4\" Combine like terms
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\n" ); document.write( " Now the quadratic is in vertex form \"y=a%28x-h%29%5E2%2Bk\" where \"a=-1\", \"h=3%2F2\", and \"k=-3%2F4\". Remember (h,k) is the vertex and \"a\" is the stretch/compression factor.
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\n" ); document.write( " Check:
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\n" ); document.write( " Notice if we graph the original equation \"y=-1x%5E2%2B3x-3\" we get:
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\n" ); document.write( " \"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C-1x%5E2%2B3x-3%29\" Graph of \"y=-1x%5E2%2B3x-3\". Notice how the vertex is (\"3%2F2\",\"-3%2F4\").
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\n" ); document.write( " Notice if we graph the final equation \"y=-1%28x-3%2F2%29%5E2-3%2F4\" we get:
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\n" ); document.write( " \"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C-1%28x-3%2F2%29%5E2-3%2F4%29\" Graph of \"y=-1%28x-3%2F2%29%5E2-3%2F4\". Notice how the vertex is also (\"3%2F2\",\"-3%2F4\").
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\n" ); document.write( " So if these two equations were graphed on the same coordinate plane, one would overlap another perfectly. So this visually verifies our answer.
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\n" ); document.write( "\n" ); document.write( "Since we know the vertex is (\"3%2F2\",\"-3%2F4\") or (1.5,-0.75), this is one point on the graph. \r
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\n" ); document.write( "\n" ); document.write( "Now lets pick any point after \"x=1.5\". Lets evaluate \"x=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=-x%5E2%2B3x-3\" Start with the given polynomial\r
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\n" ); document.write( "\n" ); document.write( "\"f%282%29=-%282%29%5E2%2B3%282%29-3\" Plug in \"x=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%282%29=-%284%29%2B3%282%29-3\" Raise 2 to the second power to get 4\r
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\n" ); document.write( "\n" ); document.write( "\"f%282%29=-%284%29%2B6-3\" Multiply 3 by 2 to get 6\r
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\n" ); document.write( "\n" ); document.write( "\"f%282%29=-1\" Now combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So we get the point (2,-1)\r
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\n" ); document.write( "\n" ); document.write( "Lets pick another value \"x=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=-x%5E2%2B3x-3\" Start with the given polynomial\r
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\n" ); document.write( "\n" ); document.write( "\"f%283%29=-%283%29%5E2%2B3%283%29-3\" Plug in \"x=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%283%29=-%289%29%2B3%283%29-3\" Raise 3 to the second power to get 9\r
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\n" ); document.write( "\n" ); document.write( "\"f%283%29=-%289%29%2B9-3\" Multiply 3 by 3 to get 9\r
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\n" ); document.write( "\n" ); document.write( "\"f%283%29=-3\" Now combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So another point is (3,-3)\r
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\n" ); document.write( "\n" ); document.write( "Now since the graph is symmetrical with respect to the axis of symmetry, this means x-values on the other side of the vertex will have the same y-values as their respective counterparts. For instance, the counterpart to \"x=2\" is \"x=1\" and the counterpart to \"x=3\" is \"x=0\" (notice they are the same distance away from the vertex along the x-axis)\r
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\n" ); document.write( "\n" ); document.write( "So here's the table of suitable values\r
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xy
0-3
1-1
1.5-0.75
2-1
3-3
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=-x%5E2%2B3x-3\" and the table of points we get\r
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\n" ); document.write( "\n" ); document.write( "Since the points lie on the curve, this verifies our answer.
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