document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1026216>Question 1026216</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The athletic department at pi high school is planning a circular track for 440 yards long the area inside the track will be planted with Sod about how many square yards of sod will be needed round answer to the nearest 100 yd.² </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #641532 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=641532\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "If it is a circular track<BR>\n" );
document.write( "of 440 yards long.(Circumference)<BR>\n" );
document.write( "Circumference = Pi x diameter<BR>\n" );
document.write( "440 = Pi x 2r (Diameter = 2 x radius)<BR>\n" );
document.write( "Radius = 440/2 x Pi<BR>\n" );
document.write( "Area of circle = Pi x (440/2 x Pi)^2<BR>\n" );
document.write( "Area of circle = 15406.i9 yds^2<BR>\n" );
document.write( "= 15,400 yds^2 (nearest 100 yd^2)<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
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