document.write( "Question 1026192: The currrent, I0 (measured in amperes), decreases to I amperes after t seconds according to the formula I = I0e−0.51t. When 25 amperes decreases to 2.5 amperes, the equation is 2.5 = 25e−0.51t. Rounded to the nearest tenth of a second, how long, t, does it take for the current to decrease from 25 amps to 2.5 amps? \n" ); document.write( "
Algebra.Com's Answer #641523 by robertb(5830)\"\" \"About 
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\"I+=+I%5B0%5De%5E%28-0.51t%29\"\r
\n" ); document.write( "\n" ); document.write( "When \"I%5B0%5D+=+25\" and I = 2.5, we have \"2.5+=+25e%5E%28-0.51t%29\". \r
\n" ); document.write( "\n" ); document.write( "==> \"e%5E%280.51t%29+=+25%2F2.5+=+10\"\r
\n" ); document.write( "\n" ); document.write( "==> 0.51t = ln10 ==> \"t+=+ln10%2F0.51+=+4.5\"seconds.\r
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