document.write( "Question 1026268: x^2-3>2x \n" ); document.write( "
Algebra.Com's Answer #641508 by kekegeter (97)\"\" \"About 
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x^2-2x-3>0
\n" ); document.write( "x^2-3x+x-3>0
\n" ); document.write( "x[x^2/x-3x/x]+(x-3)>0
\n" ); document.write( "x(x-3)+(x-3)>0
\n" ); document.write( "(x-3)(x+1)>0
\n" ); document.write( "x-3=0
\n" ); document.write( "x+1=0
\n" ); document.write( "x=3
\n" ); document.write( "x=3
\n" ); document.write( "x=-1
\n" ); document.write( "x<-1
\n" ); document.write( "-1\n" ); document.write( "x>3
\n" ); document.write( "x^2-3>2x
\n" ); document.write( "(-2)^2-3>2(-2)
\n" ); document.write( "x<-1
\n" ); document.write( "x>3 \n" ); document.write( "
\n" );