document.write( "Question 1026251: Assume that the probability of the birth of a child of a particular sex is 50%. In a family with 4 children, what is the probability that:
\n" ); document.write( "a). all children are boys
\n" ); document.write( "b). all children are the same sex
\n" ); document.write( "c).there is at least one boy\r
\n" ); document.write( "\n" ); document.write( "I tried dividing out 50%, but I'm just more confused.
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Algebra.Com's Answer #641485 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's list out the sample space. This is the entire set of all possibilities\r
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\n" ); document.write( "\n" ); document.write( "Group 1:
\n" ); document.write( "BBBB\r
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\n" ); document.write( "\n" ); document.write( "Group 2:
\n" ); document.write( "BBBG
\n" ); document.write( "BBGB
\n" ); document.write( "BGBB
\n" ); document.write( "GBBB\r
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\n" ); document.write( "\n" ); document.write( "Group 3:
\n" ); document.write( "BBGG
\n" ); document.write( "BGBG
\n" ); document.write( "BGGB
\n" ); document.write( "GBGB
\n" ); document.write( "GGBB
\n" ); document.write( "GBBG\r
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\n" ); document.write( "\n" ); document.write( "Group 4:
\n" ); document.write( "GGGB
\n" ); document.write( "GGBG
\n" ); document.write( "GBGG
\n" ); document.write( "BGGG\r
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\n" ); document.write( "\n" ); document.write( "Group 5:
\n" ); document.write( "GGGG\r
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\n" ); document.write( "\n" ); document.write( "B represents a boy. G represents a girl.
\n" ); document.write( "Group 1 shows that there is only one way to have all 4 boys and no girls.
\n" ); document.write( "Group 2 shows there are 4 ways to have three boys and one girl.
\n" ); document.write( "Group 3 has 6 possibilities of having 2 boys and 2 girls.
\n" ); document.write( "Group 4 is the opposite of group 2. There are 4 ways to have 3 girls and 1 boy
\n" ); document.write( "Group 5 is the opposite of group 1. There is only one way to have 4 girls and no boys\r
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\n" ); document.write( "\n" ); document.write( "In total, there are 1+4+6+4+1 = 16 ways to have 4 kids\r
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\n" ); document.write( "\n" ); document.write( "Things to note:
\n" ); document.write( "a) There are 4 slots and 2 choices per slot. It's no coincidence that 2^4 = 2*2*2*2 = 16
\n" ); document.write( "b) The sequence 1,4,6,4,1 is found in pascals triangle\r
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\n" ); document.write( "\n" ); document.write( "Now onto the problem\r
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\n" ); document.write( "\n" ); document.write( "a). all children are boys\r
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\n" ); document.write( "\n" ); document.write( "As shown in the sample space above, there is only one way to have all 4 boys which is BBBB. The order of the boys doesn't really matter. This is out of 16 possible ways to have 4 kids. \r
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\n" ); document.write( "\n" ); document.write( "The probability is 1/16 = 0.0625 = 6.25%\r
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\n" ); document.write( "\n" ); document.write( "b). all children are the same sex\r
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\n" ); document.write( "\n" ); document.write( "\"all children are the same sex\" is basically saying \"all boys\" OR \"all girls\" (pick one side only)\r
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\n" ); document.write( "\n" ); document.write( "There are 2 ways to either have all 4 boys or have all 4 girls. This is out of 16, so 2/16 = 1/8 = 0.125 = 12.5% is the answer for part b\r
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\n" ); document.write( "\n" ); document.write( "c).there is at least one boy \r
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\n" ); document.write( "\n" ); document.write( "There are 2 ways to compute this. We could follow\r
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\n" ); document.write( "\n" ); document.write( "method 1: count the number of combinations with at least one B in them and we'd count out 15 of 16. So the probability is 15/16 = 0.9375 = 93.75%\r
\n" ); document.write( "\n" ); document.write( "OR\r
\n" ); document.write( "\n" ); document.write( "method 2: the probability of having all girls is 6.25% which is the same as the probability of having all boys. Subtract this from 100% to get 100% - 6.25% = 93.75%\r
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\n" ); document.write( "\n" ); document.write( "No matter which method you ultimatley go with, the final answer is 93.75% which can be represented as the fraction 15/16\r
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\n" ); document.write( "\n" ); document.write( "In summary, the answers are..\r
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\n" ); document.write( "\n" ); document.write( "(a) 1/16 = 0.0625 = 6.25%
\n" ); document.write( "(b) 1/8 = 0.125 = 12.5%
\n" ); document.write( "(c) 15/16 = 0.9375 = 93.75%\r
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\n" ); document.write( "\n" ); document.write( "I'm showing all 3 formats (fraction, decimal, percent) as the answer. Choose whichever answer format your teacher wants to use.
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