document.write( "Question 1026251: Assume that the probability of the birth of a child of a particular sex is 50%. In a family with 4 children, what is the probability that:
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document.write( "a). all children are boys
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document.write( "b). all children are the same sex
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document.write( "c).there is at least one boy\r
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document.write( "I tried dividing out 50%, but I'm just more confused. \n" );
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Algebra.Com's Answer #641485 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Let's list out the sample space. This is the entire set of all possibilities\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Group 1: \n" ); document.write( "BBBB\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Group 2: \n" ); document.write( "BBBG \n" ); document.write( "BBGB \n" ); document.write( "BGBB \n" ); document.write( "GBBB\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Group 3: \n" ); document.write( "BBGG \n" ); document.write( "BGBG \n" ); document.write( "BGGB \n" ); document.write( "GBGB \n" ); document.write( "GGBB \n" ); document.write( "GBBG\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Group 4: \n" ); document.write( "GGGB \n" ); document.write( "GGBG \n" ); document.write( "GBGG \n" ); document.write( "BGGG\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Group 5: \n" ); document.write( "GGGG\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "B represents a boy. G represents a girl. \n" ); document.write( "Group 1 shows that there is only one way to have all 4 boys and no girls. \n" ); document.write( "Group 2 shows there are 4 ways to have three boys and one girl. \n" ); document.write( "Group 3 has 6 possibilities of having 2 boys and 2 girls. \n" ); document.write( "Group 4 is the opposite of group 2. There are 4 ways to have 3 girls and 1 boy \n" ); document.write( "Group 5 is the opposite of group 1. There is only one way to have 4 girls and no boys\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In total, there are 1+4+6+4+1 = 16 ways to have 4 kids\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Things to note: \n" ); document.write( "a) There are 4 slots and 2 choices per slot. It's no coincidence that 2^4 = 2*2*2*2 = 16 \n" ); document.write( "b) The sequence 1,4,6,4,1 is found in pascals triangle\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now onto the problem\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a). all children are boys\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As shown in the sample space above, there is only one way to have all 4 boys which is BBBB. The order of the boys doesn't really matter. This is out of 16 possible ways to have 4 kids. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The probability is 1/16 = 0.0625 = 6.25%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b). all children are the same sex\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"all children are the same sex\" is basically saying \"all boys\" OR \"all girls\" (pick one side only)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are 2 ways to either have all 4 boys or have all 4 girls. This is out of 16, so 2/16 = 1/8 = 0.125 = 12.5% is the answer for part b\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c).there is at least one boy \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are 2 ways to compute this. We could follow\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "method 1: count the number of combinations with at least one B in them and we'd count out 15 of 16. So the probability is 15/16 = 0.9375 = 93.75%\r \n" ); document.write( "\n" ); document.write( "OR\r \n" ); document.write( "\n" ); document.write( "method 2: the probability of having all girls is 6.25% which is the same as the probability of having all boys. Subtract this from 100% to get 100% - 6.25% = 93.75%\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "No matter which method you ultimatley go with, the final answer is 93.75% which can be represented as the fraction 15/16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In summary, the answers are..\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(a) 1/16 = 0.0625 = 6.25% \n" ); document.write( "(b) 1/8 = 0.125 = 12.5% \n" ); document.write( "(c) 15/16 = 0.9375 = 93.75%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'm showing all 3 formats (fraction, decimal, percent) as the answer. Choose whichever answer format your teacher wants to use. \n" ); document.write( " |