document.write( "Question 1026256: Hi, i know this question has already been answered but i did not understand how they got the answer.
\n" ); document.write( "Simplify:
\n" ); document.write( "3^(n-1)+3^(n-1)+3^(n-1) \r
\n" ); document.write( "\n" ); document.write( "This is their working out:
\n" ); document.write( "3[3^(n-1)]
\n" ); document.write( "3^(n-1+1) <-- i'm not sure how they got +1 and isn't 3[3^(n-1)]= 9^(n-1)? , can you explain please?
\n" ); document.write( "=3^n \n" ); document.write( "

Algebra.Com's Answer #641483 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
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Number	Statement	Reason
1.	3^(n-1)+3^(n-1)+3^(n-1)	NA
2.	3 * [3^(n-1)]	Combine like terms
3.	3^1 * [3^(n-1)]	Rewriting the first '3' as '3^1'
4.	3^[1+(n-1)]	Using the rule x^y*x^z = x^(y+z)
5.	3^(1-1+n)	Associative and commutative properties of addition
6.	3^(0+n)	Combine like terms
7.	3^n	Use the rule 0+x = x

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\n" ); document.write( "\n" ); document.write( "So in the end, 3^(n-1)+3^(n-1)+3^(n-1) simplifies to 3^n\r
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\n" ); document.write( "\n" ); document.write( "The final answer is 3^n \n" ); document.write( "

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