document.write( "Question 1026213: He worked 2 part time jobs and earned 189.00 for working a total of 24 hours at both jobs. Job A 6.00 per hour and job B 9.00 per hour. How many hours did he work at job . \n" ); document.write( "
Algebra.Com's Answer #641465 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Change the question to, \"How many hours did he work at EACH job?\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "A, the hours at job A
\n" ); document.write( "B, the hours at job B\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Account for the earnings: \"6A%2B9B=189\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Account for the total hours: \"A%2BB=24\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "What to do now:
\n" ); document.write( "Simplify the earnings equation, and solve the simultaneous equations for A and B. Use the Elimination Method, IF you know it; otherwise just use substitution method.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "---
\n" ); document.write( "\"system%282A%2B3B=63%2CA%2BB=24%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"system%282A%2B3B=63%2C2A%2B2B=48%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%282A%2B3B%29-%282A%2B2B%29=63-48\"
\n" ); document.write( "\"B=63-48\"
\n" ); document.write( "\"B=15\"-------hours at job B
\n" ); document.write( "-
\n" ); document.write( "\"A=9\"-------hours at job A
\n" ); document.write( "
\n" );