document.write( "Question 1026227: Three circles of radius 1 unit fit inside a square such that the two outer circles touch the middle
\n" ); document.write( "circle and the sides of the square, as shown. Given the centres of the circle lie on the diagonal
\n" ); document.write( "of the square, find the exact area of the square.\r
\n" ); document.write( "\n" ); document.write( "http://imgur.com/2wZdTkq\r
\n" ); document.write( "\n" ); document.write( "Please incldue all working out. Thanks
\n" ); document.write( "

Algebra.Com's Answer #641463 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Look at either circle near one of the corners of the square. Draw a radius which intersects a side of the square; which is also tangent to the circle. This tangency point, and the center point of the circle, and the corner of the square, form a right isosceles triangle having two sides of 1 unit. The hypotenuse can be found:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "h for this hypotenuse, \"h=sqrt%281%5E2%2B1%5E2%29=sqrt%282%29\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You can find the length of the diagonal of the square. The diagonal contains SIX of the radii lengths (of any of the circles); but also understand the distance from corner to a nearest center of a circle...
\n" ); document.write( "and revise the sum of lengths which compose the diagonal of the outer square.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"sqrt%282%29%2Br%2B2r%2Br%2Bsqrt%282%29\"-----the length of the diagonal of the square, which simplified is...
\n" ); document.write( "\"highlight_green%284r%2B2sqrt%282%29%29\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If this solution is stopped here, can you finish answering the question?
\n" ); document.write( "
\n" );