document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1026204>Question 1026204</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let ln(x-y) = xy\r<BR>\n" );
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document.write( "find dy/dx at (1,0)<BR>\n" );
document.write( "Write the equation of the tangent line to the graph at (1,0)\r<BR>\n" );
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document.write( "please help<BR>\n" );
document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #641450 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=641450\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Take derivative of both sides with respect to x using the chain rule:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\large \frac{1}{x-y}(1 - \frac{dy}{dx}) = y + x \frac{dy}{dx}\">\r<BR>\n" );
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document.write( "(Note that xy is a product of two functions, so you have to use the product rule here)\r<BR>\n" );
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document.write( "Use some algebra to solve for dy/dx in terms of x and y. Once you have done so, plug in x = 1, y = 0. </SPAN>\n" );
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