document.write( "Question 1026160: 1. Find the expected value for the probability distribution in the table below.
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document.write( "Value Probability
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document.write( "0 0.15
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document.write( "1 0.2
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document.write( "2 0.1
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document.write( "3 0.25
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document.write( "4 0.3 \r
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document.write( "\n" );
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Algebra.Com's Answer #641423 by mathmate(429)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Question: \n" ); document.write( "Find the expected value for the probability distribution in the table below. \n" ); document.write( "Value Probability \n" ); document.write( "0 0.15 \n" ); document.write( "1 0.2 \n" ); document.write( "2 0.1 \n" ); document.write( "3 0.25 \n" ); document.write( "4 0.3 \n" ); document.write( " \n" ); document.write( "Solution: \n" ); document.write( "For a given probability distribution p(x), the expected value is given by \n" ); document.write( "E[X]=∑x*p(x) over the valid values of x. \n" ); document.write( "For the given distribution \n" ); document.write( "X P(X) \n" ); document.write( "0 0.15 \n" ); document.write( "1 0.2 \n" ); document.write( "2 0.1 \n" ); document.write( "3 0.25 \n" ); document.write( "4 0.3 \n" ); document.write( "We calculate ∑x*p(x) = 0*0.15+1*0.2+2*0.1+3*0.25+4*0.3=2.35 \n" ); document.write( "So the expected value of the distribution is 2.35. \n" ); document.write( " \n" ); document.write( " |