document.write( "Question 1026156: Two brothers leave from the same location, one in a car and the other on a bicycle, to meet up at their grandmother’s house for dinner. If one brother averages 30 miles per hour in the car and the other averages 12 miles per hour on the bicycle, then it takes the brother on the bicycle 1 hour less than 3 times as long as the other in the car. How long does it take each of them to make the trip? \n" ); document.write( "
Algebra.Com's Answer #641413 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+t+\" = time in hrs for the brother in the car
\n" ); document.write( "\"+3t+-+1+\" = time in hrs for other brother
\n" ); document.write( "Let \"+d+\" = the distance in miles they travel
\n" ); document.write( "---------------
\n" ); document.write( "Equation for brother on bicycle
\n" ); document.write( "(1) \"+d+=+12%2A%28+3t+-+1+%29+\"
\n" ); document.write( "Equation for brother in car
\n" ); document.write( "(2) \"+d+=+30t+\"
\n" ); document.write( "----------------
\n" ); document.write( "Plug (2) into (1)
\n" ); document.write( "(1) \"+30t+=+12%2A%28+3t+-+1+%29+\"
\n" ); document.write( "(1) \"+30t+=+36t+-+12+\"
\n" ); document.write( "(1) \"+6t+=+12+\"
\n" ); document.write( "(1) \"+t+=+2+\"
\n" ); document.write( "and
\n" ); document.write( "\"+3t+-+1+=+3%2A2+-+1+\"
\n" ); document.write( "\"+3t+-+1+=+5+\"
\n" ); document.write( "The car takes 2 hrs
\n" ); document.write( "The bicycle takes 5 hrs
\n" ); document.write( "---------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+d+=+30t+\"
\n" ); document.write( "(2) \"+d+=+30%2A2+\"
\n" ); document.write( "(2) \"+d+=+60+\" mi
\n" ); document.write( "and
\n" ); document.write( "(1) \"+d+=+12%2A%28+3t+-+1+%29+\"
\n" ); document.write( "(1) \"+d+=+12%2A%28+3%2A2+-+1+%29+\"
\n" ); document.write( "(1) \"+d+=+12%2A5+\"
\n" ); document.write( "(1) \"+d+=+60+\" mi
\n" ); document.write( "OK
\n" ); document.write( "
\n" );