document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=12570>Question 12570</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is the question: Mr. Smith was told by his doctor that he needed to excercise. On Monday he jogged for 2 hours and then walked 3 hours to cover 30 miles in total. On Tuesday he jogged for 2.5 hours and then walked 4 hours to cover 38.5 miles in total. Find his speed (in miles per hour) when he is jogging.(please help me!) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6414 by </B><A HREF=/tutors/aboutme.mpl?userid=AdolphousC><B>AdolphousC(70)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AdolphousC><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a system of equations problem, so you need to define your variables,<BR>\n" );
document.write( "Let J = Miles per hour while jogging, and W equal miles per hour while walking.\r<BR>\n" );
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document.write( "Now set up your two equations, your first equation will be<BR>\n" );
document.write( "2J + 3W = 30\r<BR>\n" );
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document.write( "and your second equation will be<BR>\n" );
document.write( "2.5J + 4W = 38.5 \r<BR>\n" );
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document.write( "Now you need to find a common coefficient, I am going to turn the coefficients for W into 12 by multiplying the top equation by 4 and the bottom one by 3.\r<BR>\n" );
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document.write( "4( 2J + 3W = 30 )<BR>\n" );
document.write( "3( 2.5J + 4W = 38.5 )\r<BR>\n" );
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document.write( "Now you need to multiply, and you get<BR>\n" );
document.write( "8J + 12W = 120<BR>\n" );
document.write( "7.5J + 12W = 115.5\r<BR>\n" );
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document.write( "Subtract the two equations<BR>\n" );
document.write( "0.5J = 4.5<BR>\n" );
document.write( "Divide by 0.5<BR>\n" );
document.write( "J = 9<BR>\n" );
document.write( "Which means she Jogs at 9MPH<BR>\n" );
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document.write( "Now go back and substitue 9 for J and solve for W\r<BR>\n" );
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document.write( "using the first equation ( 2J + 3W = 30 )<BR>\n" );
document.write( "2(9) + 3W = 30 Multiply<BR>\n" );
document.write( "18 + 3W = 30 Subtract<BR>\n" );
document.write( "3W = 12 Divide<BR>\n" );
document.write( "W = 4\r<BR>\n" );
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document.write( "So she can walk 4 MPH </SPAN>\n" );
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