document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1026110>Question 1026110</A>: <I><SPAN STYLE=\"word-break: break-all;\"> simplify the expression<BR>\n" );
document.write( "log3 (x+1) -log3 (3x^2-3x-6)+log3 (x-2)\r<BR>\n" );
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document.write( "The 3 on each log is lowered </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #641371 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=641371\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log3 (x+1) -log3 (3x^2-3x-6)+log3 (x-2)\r<BR>\n" );
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document.write( "<i>The 3 on each log is lowered</i><BR>\n" );
document.write( "The 3 next to each \"log\" is the base for the logarithm.\r<BR>\n" );
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document.write( "log(3,(x+1))-log(3,(3x^2-3x-6))+log(3,(x-2))<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%283%2C%28%28x%2B1%29%28x-2%29%2F%283x%5E2-3x-6%29%29%29 ALIGN=MIDDLE  ALT=\"log%283%2C%28%28x%2B1%29%28x-2%29%2F%283x%5E2-3x-6%29%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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