document.write( "Question 1026100: Imagine you are 15 years old. Your father is 45. In how many years will your father be twice as old as you? ( algebraic expression needed please and thank you) \n" ); document.write( "
Algebra.Com's Answer #641348 by mananth(16946)\"\" \"About 
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My age 15 years\r
\n" ); document.write( "\n" ); document.write( "Fathers age 45 years\r
\n" ); document.write( "\n" ); document.write( "difference = 30 years\r
\n" ); document.write( "\n" ); document.write( "let my father be twice my age after n years\r
\n" ); document.write( "\n" ); document.write( "my age after n years 15+n\r
\n" ); document.write( "\n" ); document.write( "Father's age after n years\r
\n" ); document.write( "\n" ); document.write( "45 +n\r
\n" ); document.write( "\n" ); document.write( "SO
\n" ); document.write( "45+n = 2(15+n)\r
\n" ); document.write( "\n" ); document.write( "45+n = 2n +30\r
\n" ); document.write( "\n" ); document.write( "n =15 \r
\n" ); document.write( "\n" ); document.write( "after 15 years \r
\n" ); document.write( "\n" ); document.write( "15+15 = 30 \r
\n" ); document.write( "\n" ); document.write( "15+45 = 60\r
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